2+7[Cos(x)]=4[Sin^2(x)]

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Solution for 2+7[Cos(x)]=4[Sin^2(x)] equation: 


Simplifying
2 + 7[Cos(x)] = 4[Sin2(x)]

Multiply osC * x
2 + 7[osxC] = 4[Sin2(x)]

Multiply in2S * x
2 + 7osxC = 4[in2xS]

Solving
2 + 7osxC = 4in2xS

Solving for variable 'o'.

Move all terms containing o to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 7osxC = -2 + 4in2xS

Combine like terms: 2 + -2 = 0
0 + 7osxC = -2 + 4in2xS
7osxC = -2 + 4in2xS

Divide each side by '7sxC'.
o = -0.2857142857s-1x-1C-1 + 0.5714285714in2s-1C-1S

Simplifying
o = -0.2857142857s-1x-1C-1 + 0.5714285714in2s-1C-1S

Reorder the terms:
o = 0.5714285714in2s-1C-1S + -0.2857142857s-1x-1C-1

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